Zoekresultaten

{\displaystyle {\begin{aligned}\pi \approx A_{3072}&{}=768{\sqrt {2-{\sqrt {2+{\sqrt {2+{\sqrt {2+{\sqrt {2+{\sqrt {2+{\sqrt {2+{\sqrt {2+{\sqrt {2+1}}}}}}}}}}}}}}}}}}\\&{}=3{...

2 π     e − 1 2 ( x − μ σ ) 2 {\displaystyle f(x)={\frac {1}{\sigma {\sqrt {2\pi \ }}}}\ e^{-{\frac {1}{2}}\left({\frac {x-\mu }{\sigma }}\right)^{2}}}...

t ) e − i ω t d t {\displaystyle {\mathcal {F}}(\omega )={\frac {1}{\sqrt {2\pi }}}\int _{-\infty }^{\infty }f(t)e^{-i\omega t}\,{\rm {d}}t} (Hierin is...

formule van Stirling: n ! ≈ 2 π n ( n e ) n {\displaystyle n!\approx {\sqrt {2\pi n}}\left({\frac {n}{e}}\right)^{n}} Voor kleine waarden van n {\displaystyle...

( x ) − μ σ ) 2 {\displaystyle f(x;\mu ,\sigma )={\frac {1}{x\sigma {\sqrt {2\pi }}}}\ e^{-{\frac {1}{2}}\left({\frac {\ln(x)-\mu }{\sigma }}\right)^{2}}}...

{cx^{n}}{2}}\right)}{n{\sqrt[{n}]{-cx^{n}}}}}} ∫ e − c x 2   d x = π 4 c e r f ( c x ) {\displaystyle \int e^{-cx^{2}}\ \mathrm {d} x={\sqrt {\frac {\pi }{4c}}}\mathrm...

getallen. De formule luidt: n ! ≈ 2 π n ( n e ) n {\displaystyle n!\approx {\sqrt {2\pi n}}\;\left({\frac {n}{e}}\right)^{n}} Dit betekent ruwweg dat het rechterlid...

aangetoond wordt, geldt: φ = 1 + 5 2 ≈ 1,618 {\displaystyle \varphi ={\frac {1+{\sqrt {5}}}{2}}\approx 1{,}618} Het getal is dus irrationaal, maar niet transcendent...

{1}{\sqrt {2\pi }}}\int _{-\infty }^{\infty }e^{-\left({\sqrt {a}}x+{\frac {i\omega }{2{\sqrt {a}}}}\right)^{2}+\left({\frac {i\omega }{2{\sqrt {a}}}}\right)^{2}}\...

r=θ{\displaystyle r={\sqrt {\theta }}} dubbele Fermat-spiraal: r=θ{\displaystyle r={\sqrt {\theta }}} en r=θ+π{\displaystyle r={\sqrt {\theta +\pi }}} lituus: r=1θ{\displaystyle...

{\sqrt {\tau _{1}}}{2t{\sqrt {\pi t}}}}e^{-{\tfrac {\tau _{1}}{4t}}}} , en h 2 ( t ) = 1 π τ 2 1 1 + ( t τ 2 ) 2 {\displaystyle h_{2}(t)={\frac {1}{\pi...

{\displaystyle s={\frac {1}{\sqrt {4\pi }}}=Y_{0}^{0}} p z = ( 3 4 π ) 1 / 2 z r = Y 1 0 {\displaystyle p_{z}=\left({\frac {3}{4\pi }}\right)^{1/2}{\frac {z}{r}}=Y_{1}^{0}}...

4 − π ) 3 / 2 ≈ 0.631 {\displaystyle \gamma _{1}={\frac {2{\sqrt {\pi }}(\pi -3)}{(4-\pi )^{3/2}}}\approx 0.631} De kurtosis wordt gegeven door: γ 2 =...

1 2 π σ 2   e − ( x − μ ) 2 2 σ 2 {\displaystyle f(x)\ =\ {\frac {1}{\sqrt {2\pi \sigma ^{2}}}}\ e^{-{\frac {(x-\mu )^{2}}{2\sigma ^{2}}}}} De klokvorm...

( x ) = 1 σ 2 π e − x 2 2 σ 2 {\displaystyle f(x)={\frac {1}{\sigma {\sqrt {2\pi }}}}e^{-{\frac {x^{2}}{2\sigma ^{2}}}}} Het maximum van f {\displaystyle...

{1}{\varepsilon }}\varphi \left({\frac {x}{\varepsilon }}\right)={\frac {1}{\sqrt {2\pi \varepsilon ^{2}}}}\,\exp \left(-{\frac {x^{2}}{2\varepsilon ^{2}}}\right)\...

| e − 1 2 ( x − μ ) ′   Σ − 1 ( x − μ ) . {\displaystyle {\frac {1}{\sqrt {(2\pi )^{n}|\Sigma |}}}e^{-{\tfrac {1}{2}}(x-\mu )'\ \Sigma ^{-1}(x-\mu )}...

x=&\sin(x+2\pi )=\sin(\pi -x)&\sin x=&\cos \left({\frac {\pi }{2}}-x\right)\\\cos x=&\cos(x+2\pi )=\cos(-x)&\cos x=&\sin \left({\frac {\pi }{2}}-x\right)=&\sin...

_{i=1}^{\infty }(-1)^{i-1}e^{-2i^{2}x^{2}}={\frac {\sqrt {2\pi }}{x}}\sum _{i=1}^{\infty }e^{-(2i-1)^{2}\pi ^{2}/(8x^{2})}} . Zowel de toetsingsgrootheid van...

n + 1 2 {\displaystyle f_{n}(x)={\frac {\Gamma ({\frac {n+1}{2}})}{{\sqrt {n\pi }}\,\Gamma ({\frac {n}{2}})}}\left(1+{\frac {x^{2}}{n}}\right)^{-{\frac...